AoC 2024 Day 16: Reindeer Maze

Dated Mar 9, 2026; last modified on Mon, 09 Mar 2026

Data Parsing

The input is an \(R \times C\) grid with # for a wall, S for the start tile, E for the end tile, and . for open spots.

Part One

The reindeer start at S facing East, and can move one tile at a time, increasing their score by 1 point. They can also rotate clockwise or counterclockwise 90 degrees at a time, increasing their score by 1000 points. What is the lowest score a Reindeer could possibly get?

This is a shortest paths problem where Dijkstra’s algorithm is appropriate. The nodes are tiles on the grid. The cost of an edge varies: if the next tile is in the same direction as we’re currently heading, then the cost is 1, otherwise, the cost is 1000 + 1.

References

  1. Day 16 - Advent of Code 2024. Eric Wastl. adventofcode.com . Accessed Mar 9, 2026.